tceic.com
>> >>

݋A={x4x2x+2+a=0,xR}.1AaB2aB


݋={42+=0,R}.

1

2B6(2).


:

݋A={x|x2+4x=0,xR},B={x|x2+2(a+1)x+a2-1=0,a.doc

݋A={x|x2+4x=0,xR},B={x|x2+2(a+1)x+a2-1=0,aR,xR},BA,a. :A={x|x2+...

...4,0},B={x|x2+2(a+1)x+a2-1=0,aR}.(1)AB=B,.doc

݋A={-4,0},B={x|x2+2(a+1)x+a2-1=0,aR}. (1)AB=B,a; (2)AB=B,a. ...

A={x|x2-2x-a=0,xR},B={x|x2-4x+a+6=0,xR}....doc

A={x|x2-2x-a=0,xR},B={x|x2-4x+a+6=0,xR} (1)A=B=,a; (2)AB,a;...

...ax2+3x+1=0,xR}.(1)A,a....doc

A={x|ax2+3x+1=0,xR}. (1)A,a; (2)A,a...

A={xR|ax2-3x+2=0,aR}(1)A,a....doc

A={xR|ax2-3x+2=0,aR} (1)A,a; (2)A,a, ...

...(a+1)x+a2-1=0},xR,BA,a....doc

A={x|x2+4x=0},B={x|x2+2(a+1)x+a2-1=0},xR,BA,a. :A={x|x2+4x=0}={...

A={x|ax2+2x+1=0,xR},a.(1)A,....doc

A={x|ax2+2x+1=0,xR},a. (1)A,a; (2)A,a; (3)A,a...

A={xR|ax2+4x+1=0}.,a=( )__.doc

A={xR|ax2+4x+1=0}.,a=( ) Aa=16a=0 Ba=4a=0 Ca=2a=0 Da=2a=4 B ...

A={x|ax2+2x+1=0,aR},A,a....doc

A={x|ax2+2x+1=0,aR},A,a,...:A,ax2+2x+1=0, ...

݋A={x|x-3)(x-a)=0,aR),B={x|(x-4)(x-1)=.doc

݋A={x|x-3)(x-a)=0,aR),B={x|(x-4)(x-1)=0},AB,a=( ) A31 B34 C41 D1,34 ...

A={xR|ax2+2x+1=0,aR},A....doc

{xR|ax2+2x+1=0,aR},A,a__...,a01. A=,ax2+2x+1=0,=4-4a...

݋A={x|kx2+4x+4=0,xR}.A....doc

{x|kx2+4x+4=0,xR}.A,k...:A,A={x|kx2+4x+4=0}. k...

aA={x|xR|ax2+2x+1=0,aR }....doc

aA={x|xR|ax2+2x+1=0,aR }:;;? a=0,2x+1=0,...

...R|ax2-3x-4=0},(1)A,a....doc

A={xR|ax2-3x-4=0}, (1)A,a; (2)A,a. ...

A={xR|ax2+2x+1=0},aR.1A....doc

A={xR|ax2+2x+1=0},aR.1A,A. 1A, 1...

...=x2+1,g(x)=4x+1.(1)A={x|0x4},xR,..._.doc

Af(x)=x2+1,g(x)=4x+1. (1)A={x|0x4},xR,f(x),g(x); (2)Az...

...+2=0,aR}.(1)A,a;(2)A....doc

A={x|ax2-3x+2=0,aR}. (1)A,a; (2)A,a. :(1...

...=0,aR}.(1) A,a;(2) A....doc

A={x|ax2-3x+2=0,aR}. (1) A,a; (2) A,a,; (3) A...

...+2=0(aR,xR),A,a....doc

Aax2-4x+2=0(aR,xR),A,a. [] (1)a=0,...

A={x|ax2+2x-a=0,aR},a....doc

A={x|ax2+2x-a=0,aR},a___. (1)a=0,x=0,, (2)a0,...

|
All rights reserved Powered by www.tceic.com
copyright ©right 2010-2021
zhit325@126.com